1. Khối 7
  2. Toán 7 - Tập một - Theo SGK Chân trời sáng tạo
  3. Chương 1 SỐ HỮU TỈ
  4. Bài 2. Các phép tính với số hữu tỉ
  5. Tính giá trị biểu thức có nhiều dấu ngoặc
  • Cho phép tính D=(1+0,5)−[214+(32−0,75)]D=(1+0,5)-\left[2 \dfrac{1}{4}+\left(\dfrac{3}{2}-0,75\right)\right]D=(1+0,5)−[241​+(23​−0,75)]
    D<0D<0D<0
    D>2D>2D>2
    D=0D=0D=0
    D>0D>0D>0
    Đáp án
    D<0D<0D<0
    D>2D>2D>2
    D=0D=0D=0
    D>0D>0D>0
    Giải thích
    D=(1+0,5)−[214+(32−0,75)]=(1+12)−[214+(32−34)]D=(1+0,5)-\left[2 \dfrac{1}{4}+\left(\dfrac{3}{2}-0,75\right)\right]=\left(1+\dfrac{1}{2}\right)-\left[2 \dfrac{1}{4}+\left(\dfrac{3}{2}-\dfrac{3}{4}\right)\right]D=(1+0,5)−[241​+(23​−0,75)]=(1+21​)−[241​+(23​−43​)] =(22+12)−[214+(64−34)]=\left(\dfrac{2}{2}+\dfrac{1}{2}\right)-\left[2 \dfrac{1}{4}+\left(\dfrac{6}{4}-\dfrac{3}{4}\right)\right]=(22​+21​)−[241​+(46​−43​)] =32−(214+34)=\dfrac{3}{2}-\left(2 \dfrac{1}{4}+\dfrac{3}{4}\right)=23​−(241​+43​) =32−(94+34)=\dfrac{3}{2}-\left(\dfrac{9}{4}+\dfrac{3}{4}\right)=23​−(49​+43​) =32−3=\dfrac{3}{2}-3=23​−3 =32−62=\dfrac{3}{2}-\dfrac{6}{2}=23​−26​ =−32.=\dfrac{-3}{2}.=2−3​.
    1/1
  • Bạn Việt tính giá trị biểu thức 323−[13+(12−2)]3 \dfrac{2}{3}-\left[\dfrac{1}{3}+\left(\dfrac{1}{2}-2\right)\right]332​−[31​+(21​−2)] như sau: Bước 111: 323−[13+(12−2)]=323−[13+(12−42)]=323−[13+(−32)]3 \dfrac{2}{3}-\left[\dfrac{1}{3}+\left(\dfrac{1}{2}-2\right)\right]=3 \dfrac{2}{3}-\left[\dfrac{1}{3}+\left(\dfrac{1}{2}-\dfrac{4}{2}\right)\right]=3 \dfrac{2}{3}-\left[\dfrac{1}{3}+\left(\dfrac{-3}{2}\right)\right]332​−[31​+(21​−2)]=332​−[31​+(21​−24​)]=332​−[31​+(2−3​)] Bước 222: =323−[26+(−96)]=323−(−76)=3 \dfrac{2}{3}-\left[\dfrac{2}{6}+\left(\dfrac{-9}{6}\right)\right]=3 \dfrac{2}{3}-\left(\dfrac{-7}{6}\right)=332​−[62​+(6−9​)]=332​−(6−7​) Bước 333: =113−(−76)=226−(−76)=156=\dfrac{11}{3}-\left(\dfrac{-7}{6}\right)=\dfrac{22}{6}-\left(\dfrac{-7}{6}\right)=\dfrac{15}{6}=311​−(6−7​)=622​−(6−7​)=615​ Bài toán trên làm sai từ bước nào?
    Sai từ bước 222
    Bài toán làm đúng
    Sai từ bước 333
    Sai từ bước 111
    Đáp án
    Sai từ bước 222
    Bài toán làm đúng
    Sai từ bước 333
    Sai từ bước 111
    Giải thích
    323−[13+(12−2)]=323−[13+(12−42)]=323−[13+(−32)]3 \dfrac{2}{3}-\left[\dfrac{1}{3}+\left(\dfrac{1}{2}-2\right)\right]=3 \dfrac{2}{3}-\left[\dfrac{1}{3}+\left(\dfrac{1}{2}-\dfrac{4}{2}\right)\right]=3 \dfrac{2}{3}-\left[\dfrac{1}{3}+\left(\dfrac{-3}{2}\right)\right]332​−[31​+(21​−2)]=332​−[31​+(21​−24​)]=332​−[31​+(2−3​)] =323−[26+(−96)]=323−(−76)=3 \dfrac{2}{3}-\left[\dfrac{2}{6}+\left(\dfrac{-9}{6}\right)\right]=3 \dfrac{2}{3}-\left(\dfrac{-7}{6}\right)=332​−[62​+(6−9​)]=332​−(6−7​) =113−(−76)=226−(−76)=296.=\dfrac{11}{3}-\left(\dfrac{-7}{6}\right)=\dfrac{22}{6}-\left(\dfrac{-7}{6}\right)=\dfrac{29}{6}.=311​−(6−7​)=622​−(6−7​)=629​.
    1/1
  • Giá trị của biểu thức 13−[−76−(34+0,2)]\dfrac{1}{3}-\left[\dfrac{-7}{6}-\left(\dfrac{3}{4}+0,2\right)\right]31​−[6−7​−(43​+0,2)] là
    888
    111\dfrac{1}{11}111​
    4920\dfrac{49}{20}2049​
    333
    Đáp án
    888
    111\dfrac{1}{11}111​
    4920\dfrac{49}{20}2049​
    333
    Giải thích
    13−[−76−(34+0,2)]\dfrac{1}{3}-\left[\dfrac{-7}{6}-\left(\dfrac{3}{4}+0,2\right)\right]31​−[6−7​−(43​+0,2)] =13−[−76−(34+15)]=\dfrac{1}{3}-\left[\dfrac{-7}{6}-\left(\dfrac{3}{4}+\dfrac{1}{5}\right)\right]=31​−[6−7​−(43​+51​)] =13−[−76−(1520+420)]=13−(−76−1920)=\dfrac{1}{3}-\left[\dfrac{-7}{6}-\left(\dfrac{15}{20}+\dfrac{4}{20}\right)\right]=\dfrac{1}{3}-\left(\dfrac{-7}{6}-\dfrac{19}{20}\right)=31​−[6−7​−(2015​+204​)]=31​−(6−7​−2019​) =13−(−7060−5760)=\dfrac{1}{3}-\left(\dfrac{-70}{60}-\dfrac{57}{60}\right) =31​−(60−70​−6057​) =13−(−12760)=\dfrac{1}{3}-\left(\dfrac{-127}{60}\right)=31​−(60−127​) =2060−(−12760)=\dfrac{20}{60}-\left(\dfrac{-127}{60}\right)=6020​−(60−127​) =14760=\dfrac{147}{60}=60147​ =4920=\dfrac{49}{20}=2049​
    1/1
  • Bạn Hoà tính giá trị biểu thức 23−[312+(18−0,25)]\dfrac{2}{3}-\left[3 \dfrac{1}{2}+\left(\dfrac{1}{8}-0,25\right)\right]32​−[321​+(81​−0,25)] như sau: Bước 111: =23−[312+(18−14)]=23−[312+(18−28)]=\dfrac{2}{3}-\left[3 \dfrac{1}{2}+\left(\dfrac{1}{8}-\dfrac{1}{4}\right)\right]=\dfrac{2}{3}-\left[3 \dfrac{1}{2}+\left(\dfrac{1}{8}-\dfrac{2}{8}\right)\right]=32​−[321​+(81​−41​)]=32​−[321​+(81​−82​)] =23−(312+−18)=\dfrac{2}{3}-\left(3 \dfrac{1}{2}+\dfrac{-1}{8}\right)=32​−(321​+8−1​) Bước 222: =23−(72−18)=23−(288−18)=\dfrac{2}{3}-\left(\dfrac{7}{2}-\dfrac{1}{8}\right)=\dfrac{2}{3}-\left(\dfrac{28}{8}-\dfrac{1}{8}\right)=32​−(27​−81​)=32​−(828​−81​) =23−278=\dfrac{2}{3}-\dfrac{27}{8}=32​−827​ Bước 333: =1624−8124=\dfrac{16}{24}-\dfrac{81}{24}=2416​−2481​ =−6524=\dfrac{-65}{24}=24−65​ Bạn Hoà đã làm sai từ bước nào?
    Sai từ bước 222
    Sai từ bước 111
    Bài toán làm đúng
    Sai từ bước 333
    Đáp án
    Sai từ bước 222
    Sai từ bước 111
    Bài toán làm đúng
    Sai từ bước 333
    Giải thích
    23−[312+(18−0,25)]\dfrac{2}{3}-\left[3 \dfrac{1}{2}+\left(\dfrac{1}{8}-0,25\right)\right]32​−[321​+(81​−0,25)] =23−[312+(18−14)]=\dfrac{2}{3}-\left[3 \dfrac{1}{2}+\left(\dfrac{1}{8}-\dfrac{1}{4}\right)\right]=32​−[321​+(81​−41​)] =23−[312+(18−28)]=23−(312+−18)=\dfrac{2}{3}-\left[3 \dfrac{1}{2}+\left(\dfrac{1}{8}-\dfrac{2}{8}\right)\right]=\dfrac{2}{3}-\left(3 \dfrac{1}{2}+\dfrac{-1}{8}\right)=32​−[321​+(81​−82​)]=32​−(321​+8−1​) =23−(72−18)=\dfrac{2}{3}-\left(\dfrac{7}{2}-\dfrac{1}{8}\right)=32​−(27​−81​) =23−(288−18)=\dfrac{2}{3}-\left(\dfrac{28}{8}-\dfrac{1}{8}\right)=32​−(828​−81​) =23−278=\dfrac{2}{3}-\dfrac{27}{8}=32​−827​ =1624−8124=−6524=\dfrac{16}{24}-\dfrac{81}{24}=\dfrac{-65}{24}=2416​−2481​=24−65​
    1/1
  • Bạn Minh tính giá trị biểu thức 1,5+[29−(0,3+710)]1,5+\left[\dfrac{2}{9}-\left(0,3+\dfrac{7}{10}\right)\right]1,5+[92​−(0,3+107​)] như sau: Bước 111: =1,5+[29−(310+710)]=1,5+\left[\dfrac{2}{9}-\left(\dfrac{3}{10}+\dfrac{7}{10}\right)\right]=1,5+[92​−(103​+107​)] =1,5+(29−1)=1,5+\left(\dfrac{2}{9}-1\right)=1,5+(92​−1) Bước 222: =1,5+(29−99)=1,5+\left(\dfrac{2}{9}-\dfrac{9}{9}\right)=1,5+(92​−99​) =1,5+79=1,5+\dfrac{7}{9}=1,5+97​ Bước 333: =32+79=\dfrac{3}{2}+\dfrac{7}{9}=23​+97​ =2718+1418=\dfrac{27}{18}+\dfrac{14}{18}=1827​+1814​ =4118=\dfrac{41}{18}=1841​ Bạn Minh đã làm sai từ bước nào?
    Sai từ bước 222
    Sai từ bước 111
    Bài toán làm đúng
    Sai từ bước 333
    Đáp án
    Sai từ bước 222
    Sai từ bước 111
    Bài toán làm đúng
    Sai từ bước 333
    Giải thích
    1,5+[29−(0,3+710)]=1,5+[29−(310+710)]=1,5+(29−1)1,5+\left[\dfrac{2}{9}-\left(0,3+\dfrac{7}{10}\right)\right]=1,5+\left[\dfrac{2}{9}-\left(\dfrac{3}{10}+\dfrac{7}{10}\right)\right]=1,5+\left(\dfrac{2}{9}-1\right)1,5+[92​−(0,3+107​)]=1,5+[92​−(103​+107​)]=1,5+(92​−1) =1,5+(29−99)=1,5+−79=1,5+\left(\dfrac{2}{9}-\dfrac{9}{9}\right)=1,5+\dfrac{-7}{9}=1,5+(92​−99​)=1,5+9−7​ =32+−79=2718+−1418=\dfrac{3}{2}+\dfrac{-7}{9}=\dfrac{27}{18}+\dfrac{-14}{18}=23​+9−7​=1827​+18−14​ =1318.=\dfrac{13}{18}.=1813​.
    1/1
  • Giá trị của biểu thức −324−[14−(52−98)]-\dfrac{3}{24}-\left[\dfrac{1}{4}-\left(\dfrac{5}{2}-\dfrac{9}{8}\right)\right]−243​−[41​−(25​−89​)] là
    −324-\dfrac{3}{24}−243​
    3024\dfrac{30}{24}2430​
    −3024-\dfrac{30}{24}−2430​
    111
    Đáp án
    −324-\dfrac{3}{24}−243​
    3024\dfrac{30}{24}2430​
    −3024-\dfrac{30}{24}−2430​
    111
    Giải thích
    −324−[14−(52−98)]=−324−[14−(208−98)]-\dfrac{3}{24}-\left[\dfrac{1}{4}-\left(\dfrac{5}{2}-\dfrac{9}{8}\right)\right]=-\dfrac{3}{24}-\left[\dfrac{1}{4}-\left(\dfrac{20}{8}-\dfrac{9}{8}\right)\right]−243​−[41​−(25​−89​)]=−243​−[41​−(820​−89​)] =−324−(14−118)=-\dfrac{3}{24}-\left(\dfrac{1}{4}-\dfrac{11}{8}\right)=−243​−(41​−811​) =−324−(28−118)=-\dfrac{3}{24}-\left(\dfrac{2}{8}-\dfrac{11}{8}\right)=−243​−(82​−811​) =−324−(−98)=-\dfrac{3}{24}-\left(\dfrac{-9}{8}\right)=−243​−(8−9​) =−324−(−2724)=-\dfrac{3}{24}-\left(\dfrac{-27}{24}\right)=−243​−(24−27​) =2424=\dfrac{24}{24}=2424​ =1.=1. =1.
    1/1
  • Cho phép tính B=(0,9+110)+[43−(−23+1)]B=\left(0,9+\dfrac{1}{10}\right)+\left[\dfrac{4}{3}-\left(\dfrac{-2}{3}+1\right)\right]B=(0,9+101​)+[34​−(3−2​+1)]. Chọn khẳng định đúng
    B>2B>2B>2
    B=2B=2B=2
    B<0B<0B<0
    B>4B>4B>4
    Đáp án
    B>2B>2B>2
    B=2B=2B=2
    B<0B<0B<0
    B>4B>4B>4
    Giải thích
    B=(0,9+110)+[43−(−23+1)]B=\left(0,9+\dfrac{1}{10}\right)+\left[\dfrac{4}{3}-\left(\dfrac{-2}{3}+1\right)\right]B=(0,9+101​)+[34​−(3−2​+1)] =(910+110)+[43−(−23+33)]=\left(\dfrac{9}{10}+\dfrac{1}{10}\right)+\left[\dfrac{4}{3}-\left(\dfrac{-2}{3}+\dfrac{3}{3}\right)\right]=(109​+101​)+[34​−(3−2​+33​)] =1+(43−13)=1+33=1+\left(\dfrac{4}{3}-\dfrac{1}{3}\right)=1+\dfrac{3}{3}=1+(34​−31​)=1+33​ =1+1=2=1+1=2=1+1=2
    1/1
  • Giá trị của biểu thức 58+[689−(94+12)]\dfrac{5}{8}+\left[6 \dfrac{8}{9}-\left(\dfrac{9}{4}+\dfrac{1}{2}\right)\right]85​+[698​−(49​+21​)] là
    79\dfrac{7}{9}97​
    222
    2152 \dfrac{1}{5}251​
    34372\dfrac{343}{72}72343​
    Đáp án
    79\dfrac{7}{9}97​
    222
    2152 \dfrac{1}{5}251​
    34372\dfrac{343}{72}72343​
    Giải thích
    58+[689−(94+12)]\dfrac{5}{8}+\left[6 \dfrac{8}{9}-\left(\dfrac{9}{4}+\dfrac{1}{2}\right)\right]85​+[698​−(49​+21​)] =58+[629−(188+48)]=\dfrac{5}{8}+\left[\dfrac{62}{9}-\left(\dfrac{18}{8}+\dfrac{4}{8}\right)\right]=85​+[962​−(818​+84​)] =58+(629−228)=\dfrac{5}{8}+\left(\dfrac{62}{9}-\dfrac{22}{8}\right)=85​+(962​−822​) =58+(629−114)=\dfrac{5}{8}+\left(\dfrac{62}{9}-\dfrac{11}{4}\right)=85​+(962​−411​) =58+(24836−9936)=\dfrac{5}{8}+\left(\dfrac{248}{36}-\dfrac{99}{36}\right)=85​+(36248​−3699​) =58+14936=4572+29872=\dfrac{5}{8}+\dfrac{149}{36}=\dfrac{45}{72}+\dfrac{298}{72}=85​+36149​=7245​+72298​ =34372.=\dfrac{343}{72}. =72343​.
    1/1
  • Cho phép tính C=234−[59+(76−23)]C=2 \dfrac{3}{4}-\left[\dfrac{5}{9}+\left(\dfrac{7}{6}-\dfrac{2}{3}\right)\right]C=243​−[95​+(67​−32​)]. Chọn khẳng định đúng.
    C>1C>1C>1
    C>4C>4C>4
    C<1C<1C<1
    C<0C<0C<0
    Đáp án
    C>1C>1C>1
    C>4C>4C>4
    C<1C<1C<1
    C<0C<0C<0
    Giải thích
    C=234−[59+(76−23)]=234−[59+(76−46)]C=2 \dfrac{3}{4}-\left[\dfrac{5}{9}+\left(\dfrac{7}{6}-\dfrac{2}{3}\right)\right]=2 \dfrac{3}{4}-\left[\dfrac{5}{9}+\left(\dfrac{7}{6}-\dfrac{4}{6}\right)\right]C=243​−[95​+(67​−32​)]=243​−[95​+(67​−64​)] =234−(59+36)=2 \dfrac{3}{4}-\left(\dfrac{5}{9}+\dfrac{3}{6}\right)=243​−(95​+63​) =234−(59+12)=2 \dfrac{3}{4}-\left(\dfrac{5}{9}+\dfrac{1}{2}\right)=243​−(95​+21​) =234−(1018+918)=2 \dfrac{3}{4}-\left(\dfrac{10}{18}+\dfrac{9}{18}\right)=243​−(1810​+189​) =114−1918=\dfrac{11}{4}-\dfrac{19}{18}=411​−1819​ =9936−3836=\dfrac{99}{36}-\dfrac{38}{36}=3699​−3638​ =6136=\dfrac{61}{36}=3661​
    1/1
  • Cho phép tính A=(−47−45)−[12−(−37−110)]A=\left(\dfrac{-4}{7}-\dfrac{4}{5}\right)-\left[\dfrac{1}{2}-\left(-\dfrac{3}{7}-\dfrac{1}{10}\right)\right]A=(7−4​−54​)−[21​−(−73​−101​)]. Chọn khẳng định đúng.
    A>0A>0A>0
    A<−2A<-2A<−2
    A>−2A>-2A>−2
    A<−5A<-5A<−5
    Đáp án
    A>0A>0A>0
    A<−2A<-2A<−2
    A>−2A>-2A>−2
    A<−5A<-5A<−5
    Giải thích
    A=(−47−45)−[12−(−37−110)]=−47−45−12+(−37−110)A=\left(\dfrac{-4}{7}-\dfrac{4}{5}\right)-\left[\dfrac{1}{2}-\left(-\dfrac{3}{7}-\dfrac{1}{10}\right)\right]=\dfrac{-4}{7}-\dfrac{4}{5}-\dfrac{1}{2}+\left(-\dfrac{3}{7}-\dfrac{1}{10}\right)A=(7−4​−54​)−[21​−(−73​−101​)]=7−4​−54​−21​+(−73​−101​) =−47−45−12−37−110=\dfrac{-4}{7}-\dfrac{4}{5}-\dfrac{1}{2}-\dfrac{3}{7}-\dfrac{1}{10}=7−4​−54​−21​−73​−101​ =(−47−37)−45−12−110=−77−45−12−110=\left(\dfrac{-4}{7}-\dfrac{3}{7}\right)-\dfrac{4}{5}-\dfrac{1}{2}-\dfrac{1}{10}=\dfrac{-7}{7}-\dfrac{4}{5}-\dfrac{1}{2}-\dfrac{1}{10}=(7−4​−73​)−54​−21​−101​=7−7​−54​−21​−101​ =−1−45−12−110=-1-\dfrac{4}{5}-\dfrac{1}{2}-\dfrac{1}{10} =−1−54​−21​−101​ =−1010−810−510−110=\dfrac{-10}{10}-\dfrac{8}{10}-\dfrac{5}{10}-\dfrac{1}{10}=10−10​−108​−105​−101​ =−2410=\dfrac{-24}{10}=10−24​ =−125=\dfrac{-12}{5}=5−12​
    1/1
  • Bạn An tính giá trị biểu thức −23−[(−14)−(54+−38)]\dfrac{-2}{3}-\left[\left(-\dfrac{1}{4}\right)-\left(\dfrac{5}{4}+\dfrac{-3}{8}\right)\right]3−2​−[(−41​)−(45​+8−3​)] như sau: Bước 111: −23−[(−14)−(54+−38)]=−23−[(−14)−(108+−38)]=−23−[(−14)−78]\dfrac{-2}{3}-\left[\left(-\dfrac{1}{4}\right)-\left(\dfrac{5}{4}+\dfrac{-3}{8}\right)\right]=\dfrac{-2}{3}-\left[\left(-\dfrac{1}{4}\right)-\left(\dfrac{10}{8}+\dfrac{-3}{8}\right)\right]=\dfrac{-2}{3}-\left[\left(-\dfrac{1}{4}\right)-\dfrac{7}{8}\right]3−2​−[(−41​)−(45​+8−3​)]=3−2​−[(−41​)−(810​+8−3​)]=3−2​−[(−41​)−87​] Bước 222: =−23−[(−28)−78]=−23−(−58)=\dfrac{-2}{3}-\left[\left(-\dfrac{2}{8}\right)-\dfrac{7}{8}\right]=\dfrac{-2}{3}-\left(\dfrac{-5}{8}\right)=3−2​−[(−82​)−87​]=3−2​−(8−5​) Bước 333: =−1624−(−1524)=−124=\dfrac{-16}{24}-\left(\dfrac{-15}{24}\right)=\dfrac{-1}{24}=24−16​−(24−15​)=24−1​ Bạn An đã làm sai từ bước nào?
    Bài toán làm đúng
    Sai từ bước 333
    Sai từ bước 222
    Sai từ bước 111
    Đáp án
    Bài toán làm đúng
    Sai từ bước 333
    Sai từ bước 222
    Sai từ bước 111
    Giải thích
    −23−[(−14)−(54+−38)]=−23−[(−14)−(108+−38)]\dfrac{-2}{3}-\left[\left(-\dfrac{1}{4}\right)-\left(\dfrac{5}{4}+\dfrac{-3}{8}\right)\right]=\dfrac{-2}{3}-\left[\left(-\dfrac{1}{4}\right)-\left(\dfrac{10}{8}+\dfrac{-3}{8}\right)\right]3−2​−[(−41​)−(45​+8−3​)]=3−2​−[(−41​)−(810​+8−3​)] =−23−[(−14)−78]=\dfrac{-2}{3}-\left[\left(-\dfrac{1}{4}\right)-\dfrac{7}{8}\right] =3−2​−[(−41​)−87​] =−23−[(−28)−78]=\dfrac{-2}{3}-\left[\left(-\dfrac{2}{8}\right)-\dfrac{7}{8}\right]=3−2​−[(−82​)−87​] =−23−(−98)=\dfrac{-2}{3}-\left(\dfrac{-9}{8}\right) =3−2​−(8−9​) =−1624−(−2724)=\dfrac{-16}{24}-\left(\dfrac{-27}{24}\right)=24−16​−(24−27​) =1124=\dfrac{11}{24}=2411​
    1/1
  • Giá trị của biểu thức 115+[0,75+(16−32)]1 \dfrac{1}{5}+\left[0,75+\left(\dfrac{1}{6}-\dfrac{3}{2}\right)\right]151​+[0,75+(61​−23​)]
    −0,5-0,5−0,5
    333
    121212
    3760\dfrac{37}{60}6037​
    Đáp án
    −0,5-0,5−0,5
    333
    121212
    3760\dfrac{37}{60}6037​
    Giải thích
    115+[0,75+(16−32)]=65+[34+(16−96)]=65+(34+−86)1 \dfrac{1}{5}+\left[0,75+\left(\dfrac{1}{6}-\dfrac{3}{2}\right)\right]=\dfrac{6}{5}+\left[\dfrac{3}{4}+\left(\dfrac{1}{6}-\dfrac{9}{6}\right)\right]=\dfrac{6}{5}+\left(\dfrac{3}{4}+\dfrac{-8}{6}\right)151​+[0,75+(61​−23​)]=56​+[43​+(61​−69​)]=56​+(43​+6−8​) =65+(34+−43)=\dfrac{6}{5}+\left(\dfrac{3}{4}+\dfrac{-4}{3}\right)=56​+(43​+3−4​) =65+(912+−1612)=\dfrac{6}{5}+\left(\dfrac{9}{12}+\dfrac{-16}{12}\right)=56​+(129​+12−16​) =65+−712=7260+−3560=\dfrac{6}{5}+\dfrac{-7}{12}=\dfrac{72}{60}+\dfrac{-35}{60}=56​+12−7​=6072​+60−35​ =3760=\dfrac{37}{60}=6037​
    1/1

hoclieuthongminh.com © 2022

  • Sitemap
  • Home
  • Home